Creating a mathematical model for population growth involves using mathematical equations to predict how populations change over time based on various factors. These models can vary in complexity, from simple linear growth to more complex exponential or logistic growth models. In this article, we present three diverse, practical examples to illustrate how to create mathematical models for population growth.
This model assumes a constant rate of growth over time. It can be useful for small populations in stable environments where resources are abundant.
In this example, let’s consider a small town that has a population of 1,000 people. The town experiences a steady increase of 50 people each year due to births and immigration.
The formula for a linear growth model is:
\[ P(t) = P_0 + rt \]
Where:
Using our example values:
Plugging these values into the equation:
\[ P(5) = 1000 + 50(5) \]
Calculating:
\[ P(5) = 1000 + 250 = 1250 \]
Exponential growth occurs when the growth rate of a population is proportional to its current size, often seen in ideal conditions with unlimited resources.
Let’s consider a bacteria culture that starts with 100 bacteria and doubles every hour. The exponential growth formula is:
\[ P(t) = P_0 imes e^{rt} \]
Where:
Assuming a doubling time of 1 hour, we can express the growth rate (r) as:
Using our example values:
Plugging these values into the equation:
\[ P(3) = 100 imes e^{(ln(2) imes 3)} \]
Calculating:
\[ P(3) = 100 imes 2^3 = 100 imes 8 = 800 \]
The logistic growth model accounts for environmental limits on population growth. It is often more realistic for populations in a limited environment.
Consider a wildlife reserve that can support a maximum of 5,000 deer. The current deer population is 1,000, and the growth rate is 0.1 per year. The logistic growth model is given by:
\[ P(t) =
rac{K}{1 +
rac{K - P_0}{P_0} e^{-rt}} \]
Where:
Using our example values:
Plugging these values into the equation:
\[ P(10) =
rac{5000}{1 +
rac{5000 - 1000}{1000} e^{-0.1 imes 10}} \]
Calculating:
First, evaluate the exponent:
\[ e^{-1} ext{ (approximately 0.3679)} \]
Then calculate:
\[ P(10) =
rac{5000}{1 + 4 imes 0.3679} =
rac{5000}{1 + 1.4716} =
rac{5000}{2.4716} ext{ (approximately 2029)} \]
By exploring these examples of creating a mathematical model for population growth, students can gain a deeper understanding of how populations change and the factors influencing those changes.