Proof by contrapositive is a powerful technique in mathematical reasoning. It involves proving that if a statement implies another, then the negation of the second statement implies the negation of the first. This method is particularly useful when the direct proof of a statement is complex or convoluted. Instead of proving the statement directly, we can prove its contrapositive, which is logically equivalent. Below are three diverse examples that illustrate this proof strategy.
This example demonstrates how to prove a property about even numbers and their squares using proof by contrapositive.
If we want to show that if a number is even, then its square is even, we can instead prove the contrapositive: if the square of a number is not even, then the number itself is not even.
We start with the statement: If n is an even number, then n² is even.
The contrapositive would be: If n² is odd, then n is odd.
To prove this, we assume that n² is odd. From the definition of odd numbers, we can express n² as n² = 2k + 1 for some integer k. Now we can consider the implications:
Thus, we conclude that if n² is odd, then n must also be odd, proving the contrapositive and, consequently, the original statement.
This example highlights the relationship between odd and even numbers, reinforcing the understanding of number properties.
In geometry, we often deal with properties of shapes. Here, we will prove a statement regarding triangles using proof by contrapositive.
We want to show: If a triangle is equilateral, then it has three equal angles. Instead, we will prove the contrapositive: If a triangle does not have three equal angles, then it is not equilateral.
Assuming that a triangle does not have three equal angles means at least one angle is different from the others. If we have a triangle with angles A, B, and C, we denote one angle, say A, as differing from the others, leading us to:
Thus, we conclude that if a triangle does not have three equal angles, it cannot be equilateral, thereby proving the contrapositive and the original statement.
This example is beneficial for students learning about triangle properties and helps reinforce foundational concepts in geometry.
This example illustrates the application of proof by contrapositive in relation to prime numbers and their properties.
We aim to show: If p is a prime number, then p has no divisors other than 1 and p itself. We will instead prove the contrapositive: If p has a divisor other than 1 and p, then p is not a prime number.
Assuming p has a divisor d such that 1 < d < p, it follows that:
Thus, we conclude that if p has a divisor other than 1 and p, then it is not prime, proving the contrapositive and thus the original statement.
This example serves as a fundamental concept in number theory and is particularly useful for students studying prime numbers and divisibility rules.