3 Practical Examples of Inclusion-Exclusion Principle

Explore three detailed examples of the Inclusion-Exclusion Principle in combinatorial problem solving.
By Jamie

Understanding the Inclusion-Exclusion Principle

The Inclusion-Exclusion Principle is a fundamental combinatorial method used to calculate the size of the union of multiple sets. It allows us to avoid double-counting elements that belong to more than one set. This principle is particularly useful in problems involving overlapping groups, making it a vital tool in combinatorial mathematics.

Example 1: Survey Responses from Students

In a university, a survey is conducted among students to understand their participation in various extracurricular activities. The survey results show that:

  • 60 students participate in sports.
  • 45 students participate in music.
  • 30 students participate in both sports and music.

To find out how many students are involved in at least one of these activities, we can use the Inclusion-Exclusion Principle.

  1. Let A be the set of students who participate in sports, and B be the set of students who participate in music.
  2. The number of students in at least one activity is given by:

    |A ∪ B| = |A| + |B| - |A ∩ B|

    Plugging in the values:
    |A ∪ B| = 60 + 45 - 30 = 75

Thus, 75 students are involved in at least one extracurricular activity.

Notes:

  • This example can be extended by adding more activities and applying the principle iteratively.
  • If additional intersections are known, they can be included to refine the calculation further.

Example 2: Overlapping Birthdays in a Class

Imagine a class of 30 students. Some students share the same birthday. The data collected shows:

  • 12 students have birthdays in January.
  • 10 students have birthdays in February.
  • 5 students have birthdays in both January and February.

To determine how many students have their birthdays in either January or February, we again apply the Inclusion-Exclusion Principle.

  1. Let A be the set of students with January birthdays, and B be the set with February birthdays.
  2. The total number of students with birthdays in either month is calculated as follows:

    |A ∪ B| = |A| + |B| - |A ∩ B|

    Substituting the values:
    |A ∪ B| = 12 + 10 - 5 = 17

Therefore, 17 students have their birthdays in January or February.

Notes:

  • This example can be adjusted to account for more months and their overlaps, enhancing its complexity.
  • Consideration of students with birthdays in other months can be included to broaden the scope.

Example 3: Customers Buying Products

A store sells three types of products: electronics, clothing, and home goods. During a promotional event, the following data was collected:

  • 200 customers bought electronics.
  • 150 customers bought clothing.
  • 100 customers bought both electronics and clothing.
  • 50 customers bought home goods, and 25 of those also bought electronics.

To find out the total number of customers who purchased at least one type of product, we will apply the Inclusion-Exclusion Principle.

  1. Define sets:

    • Let A be customers who bought electronics.
    • Let B be customers who bought clothing.
    • Let C be customers who bought home goods.
  2. We need to calculate |A ∪ B ∪ C|. The formula is:

    |A ∪ B ∪ C| = |A| + |B| + |C| - |A ∩ B| - |A ∩ C| - |B ∩ C| + |A ∩ B ∩ C|

    In this example, we lack data on |B ∩ C| and |A ∩ B ∩ C|, so we will only calculate the available data:

    |A ∪ B| = |A| + |B| - |A ∩ B| = 200 + 150 - 100 = 250

    Since we do not know the overlaps with home goods, we conclude with the known total:

    |A ∪ B ∪ C| ≥ 250 + 50 = 300 (accounting for home goods).

Thus, at least 300 customers purchased at least one type of product during the event.

Notes:

  • More precise data on overlaps would yield a more accurate total.
  • This scenario can be expanded to include additional product categories and customer behaviors.