Linear equations are mathematical statements that show the equality of two expressions. They typically take the form of ax + b = c
, where x
is the variable we want to solve for. Solving linear equations is essential in various real-world applications, from budgeting to physics. In this article, we’ll explore three practical examples of solving linear equations.
When planning a party, you want to keep track of your expenses. Let’s say you have a total budget of \(200, and you’ve already spent \)50 on decorations. You want to buy some snacks and drinks, costing $5 each. How many snacks and drinks can you buy?
First, you set up the equation based on your budget:
The equation to represent this situation is:
$$
50 + 5x = 200
$$
Where x
is the number of snacks and drinks. Now, let’s solve for x
:
You can buy 30 snacks and drinks for your party.
Notes: If the cost of snacks and drinks changes, adjust the equation accordingly. For example, if each snack/drink costs \(6 instead of \)5, the equation would be 50 + 6x = 200
.
Imagine you’re planning a road trip and need to know how long it will take you to reach your destination. You plan to drive at a speed of 60 miles per hour and want to cover a distance of 240 miles. You can use a linear equation to determine how many hours your trip will take.
The equation that represents distance is:
$$
Distance = Speed \times Time
$$
Let’s define the variables:
t
hoursThus, the equation becomes:
$$
60t = 240
$$
Now, let’s solve for t
:
It will take you 4 hours to reach your destination.
Notes: If you need to include breaks, you can modify the equation by adding a variable for breaks. For example, if you plan to take a 30-minute break, you can adjust the total time to t + 0.5
.
Let’s say you’re shopping for a new jacket. The jacket is on sale for \(80, and you have a coupon that gives you a discount of \)20 off the regular price. You want to find out the regular price of the jacket before the discount.
You can set up the equation as follows:
p
Thus, the equation is:
$$
p - 20 = 80
$$
Now, let’s solve for p
:
The regular price of the jacket is $100.
Notes: If there are additional discounts or taxes, you can modify the equation to include those factors as well. For example, if there’s a tax of $10, the equation might look different, such as p - 20 + 10 = 80
.