To determine the empirical formula of a compound using combustion analysis, we measure the amounts of carbon dioxide (CO₂) and water (H₂O) produced when a sample of the compound is burned. By analyzing these products, we can deduce the number of moles of each element in the original compound.
Let’s say we combust a sample of a compound and collect the following data:
Calculating moles of CO₂:
[
\text{Moles of CO₂} = \frac{\text{mass of CO₂}}{\text{molar mass of CO₂}} = \frac{2.20 g}{44.01 g/mol} = 0.0500 mol
]
Calculating moles of H₂O:
[
\text{Moles of H₂O} = \frac{\text{mass of H₂O}}{\text{molar mass of H₂O}} = \frac{0.90 g}{18.02 g/mol} = 0.0500 mol
]
From CO₂: Each mole of CO₂ contains 1 mole of C.
[
\text{Moles of C} = 0.0500 mol
]
From H₂O: Each mole of H₂O contains 2 moles of H.
[
\text{Moles of H} = 0.0500 mol \times 2 = 0.1000 mol
]
For this example, we will assume there are no other elements (like O) in the original compound.
Now we have:
To find the simplest ratio:
The empirical formula for the compound is CH₂.
By following the steps outlined in this example, you can effectively determine the empirical formula of a compound from combustion analysis. Understanding this process is essential for chemists and can be applied in various scientific fields.