Understanding the Impact of Temperature on Gas Pressure

In this article, we will explore how temperature influences gas pressure in a closed system, utilizing the Ideal Gas Law. We will provide practical examples to illustrate this fundamental concept in chemistry.
Written by
Jamie

The Ideal Gas Law, represented by the formula PV = nRT, describes the relationship between pressure (P), volume (V), number of moles (n), the gas constant (R), and temperature (T) of an ideal gas. In a closed system, when the volume remains constant, changes in temperature directly affect the pressure.

Example 1: Heating a Sealed Container

Scenario:

Consider a sealed container with a volume of 2.0 liters filled with a gas at an initial temperature of 20°C (293 K) and an initial pressure of 1.0 atm. We want to investigate what happens when we increase the temperature to 80°C (353 K).

Calculation:

Using the Ideal Gas Law, we can rearrange the formula to find the new pressure:

  1. Initial Conditions:

    • V = 2.0 L
    • T₁ = 293 K
    • P₁ = 1.0 atm
  2. Final Conditions:

    • T₂ = 353 K
    • V = 2.0 L (constant)
  3. Using the formula:

    Since volume is constant, we can use the relationship:

    \\( \frac{P_1}{T_1} = \frac{P_2}{T_2} \)

    Rearranging gives us:
    \\( P_2 = P_1 \times \frac{T_2}{T_1} \)

  4. Plugging in the values:
    \\( P_2 = 1.0 \times \frac{353}{293} \)
    \\( P_2 ≈ 1.20 \, atm \)

Conclusion:

As the temperature increased from 20°C to 80°C, the pressure in the container rose from 1.0 atm to approximately 1.20 atm, demonstrating the direct relationship between temperature and pressure in a closed system.

Example 2: Cooling a Gas in a Balloon

Scenario:

Imagine a balloon filled with air at an initial temperature of 30°C (303 K) and a pressure of 1.5 atm. We then place this balloon in a refrigerator, lowering the temperature to 10°C (283 K).

Calculation:

  1. Initial Conditions:

    • V = constant (the balloon expands or contracts)
    • T₁ = 303 K
    • P₁ = 1.5 atm
  2. Final Conditions:

    • T₂ = 283 K
  3. Using the formula:
    \\( P_2 = P_1 \times \frac{T_2}{T_1} \)

  4. Plugging in the values:
    \\( P_2 = 1.5 \times \frac{283}{303} \)
    \\( P_2 ≈ 1.40 \, atm \)

Conclusion:

When the temperature decreased from 30°C to 10°C, the pressure inside the balloon dropped from 1.5 atm to approximately 1.40 atm. This further confirms that lowering the temperature in a closed system results in a decrease in gas pressure.

Summary

These examples illustrate the fundamental relationship governed by the Ideal Gas Law: as temperature increases in a closed system, pressure increases, and conversely, as temperature decreases, pressure decreases. Understanding this relationship is crucial for various applications in chemistry, physics, and engineering.

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