\[ PV = nRT \]
Where:
To find the number of moles (n), we can rearrange the equation:
\[ n = \frac{PV}{RT} \]
A gas occupies a volume of 10.0 liters at a pressure of 2.0 atm and a temperature of 300 K. How many moles of gas are present?
Identify given values:
Plug the values into the rearranged Ideal Gas Law:
\[ n = \frac{PV}{RT} = \frac{(2.0 \, \text{atm})(10.0 \, \text{L})}{(0.0821 \, \text{L·atm/(K·mol)})(300 \, K)} \]
Calculate:
\[ n = \frac{20.0 \, \text{atm·L}}{24.63 \, \text{L·atm/(K·mol)}} \approx 0.812 \, \text{mol} \]
Approximately 0.812 moles of gas are present in the sample.
A 5.0 L container holds a gas at a pressure of 1.5 atm and a temperature of 273 K. How many moles of gas does the container hold?
Identify given values:
Use the Ideal Gas Law:
\[ n = \frac{PV}{RT} = \frac{(1.5 \, \text{atm})(5.0 \, \text{L})}{(0.0821 \, \text{L·atm/(K·mol)})(273 \, K)} \]
Calculate:
\[ n = \frac{7.5 \, \text{atm·L}}{22.41 \, \text{L·atm/(K·mol)}} \approx 0.334 \, \text{mol} \]
There are approximately 0.334 moles of gas in the container under these conditions.