A galvanic cell, also known as a voltaic cell, is an electrochemical cell that converts chemical energy into electrical energy through spontaneous redox reactions. It consists of two electrodes: an anode (negative electrode) and a cathode (positive electrode), immersed in an electrolyte solution.
In this example, we will consider a galvanic cell consisting of a zinc electrode in a zinc sulfate solution and a copper electrode in a copper sulfate solution.
Anode (Oxidation):
Zn(s) → Zn²⁺(aq) + 2e⁻
Cathode (Reduction):
Cu²⁺(aq) + 2e⁻ → Cu(s)
To calculate the cell potential (E°) of the galvanic cell, we will use the standard reduction potentials from a table:
The cell potential is calculated as follows:
E° = E°(cathode) - E°(anode)
E° = (+0.34 V) - (-0.76 V)
E° = +1.10 V
This galvanic cell has a standard cell potential of +1.10 V, indicating a spontaneous reaction.
A common example of a galvanic cell is the lead-acid battery, which consists of lead dioxide (PbO₂) as the positive electrode and sponge lead (Pb) as the negative electrode, with sulfuric acid (H₂SO₄) as the electrolyte.
Anode (Oxidation):
Pb(s) + SO₄²⁻(aq) → PbSO₄(s) + 2e⁻
Cathode (Reduction):
PbO₂(s) + 3H⁺(aq) + SO₄²⁻(aq) + 2e⁻ → PbSO₄(s) + 2H₂O(l)
Using standard reduction potentials:
The cell potential is calculated as:
E° = E°(cathode) - E°(anode)
E° = (+1.46 V) - (-0.13 V)
E° = +1.59 V
The lead-acid battery has a standard cell potential of +1.59 V, showcasing its effectiveness in providing electrical energy.
Understanding galvanic cells involves recognizing their components, how they function, and the methods to calculate their cell potential. By studying practical examples such as the zinc-copper cell and the lead-acid battery, you can gain insights into the principles of electrochemistry and their applications in real-world scenarios.